50b^2-288=0

Solution for 50b^2-288=0 equation:

50b^2-288=0

a = 50; b = 0; c = -288;
Δ = b2-4ac
Δ = 02-4·50·(-288)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240}{2*50}=\frac{-240}{100}
=-2+2/5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240}{2*50}=\frac{240}{100}
=2+2/5
$